Sunday, February 21, 2010

What is missing?

Hi, kids. This e-tivity is about using our knowledge and our ability to find information to solve a math problem.
By the end, you'll be able to
  • develop a strategy to solve a problem when a data is missing and support the choices you make
Average online time: 20 min
Average offline time time: 10 min

TASK
Taking into account the information below

1) choose one of the flights,
2) find out what time it will arrive at its final destination &
3) explain the procedure you used to find the solution















Post your comment including answers to all the above numerals.
See you around!

This page might help you out:


31 comments:

  1. Maria Alejandra EscalanteFebruary 22, 2010 at 2:05 p.m.

    flight 012
    from bogota at 8:00am.
    speed 14. 5 k/min
    14.5 x 8 = 12:00
    In cali at 12:00
    by: Maria Alejandra

    ReplyDelete
  2. the time,speed,and distances of bogota -cali is
    t=20,6
    v=14,5
    d=299,84
    medellin- bogota is
    t=170
    v=14,5
    d=247,44
    cartagena - pasto
    t=717
    v=14,5
    d=1039,89
    gabriela cortes 5b

    ReplyDelete
  3. hi miss my answers are this :
    1.012
    2.8+14.5=22.5i sum 8 times 14.5
    3.i sum 8 times 14.5=225
    they arrive at 2:25
    by miss

    juanita brando

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  4. I don´t know how to find the answer because I need to know how many are the km to the departs from until arrives at

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  5. Miss I dont uderstand I think that you can explain me in class...... :)

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  6. Bogota to Cali
    It will arrive at 8:21am
    The procedure was: 299.84 km / 14.5km/min=20.67 minutes

    ReplyDelete
  7. miss I dont unerstand the problem good can you explain

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  8. Maria Jose Pulido Matallana 5AFebruary 22, 2010 at 9:07 p.m.

    the flight 012 from bogota at 8 :00 am speed exacly 14.5 km per minute

    and 14.5 x 8=12:00 and finally in cali at 12:00

    i understod verywell

    ReplyDelete
  9. Miss I don't understand, but my mother help me.
    1) VUELO 214
    2) The distance of the flight Medellin to Bogota, is 247,44 KM
    3) 247,44 km / 14,5 Km = 17,06
    09:35 AM + 17,06 Min = 09:52 AM
    The flight arrives at 09:52 AM

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  10. 012
    bogota 8:00am
    14.5x8=12
    so they arrive at 12:00 in Cali

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  11. PROCEDURE WITHOUT DATA:
    alethia I doesnt know the km from one city to other so I will said that X are the numbers of kms form a place to other, Y are the minutes, Z is the result.
    answer:
    if the figth of bogota is 012
    so
    Xkm / 14.5km/h = Ymins
    8:00am +Ymins = Z
    so Z will be the time that the fligth takes to arrives.
    -----------------------------------------------
    PROCEDURE WITH THE DATA
    miss the page that said that it might help yo sai that form bogota to cali ther is a distance pf 299.84KM

    299.84KM/14.5km/h= 20.67 mins
    8:00am+20.67mis = 8:20 am
    you will arrive to cali at 8:20am

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  12. Miss I dont understand good that proble i think that inclass you can explain us thanks.... ;)

    ReplyDelete
  13. maria alejandra esacalante pMarch 1, 2010 at 2:20 p.m.

    here are the corrections:
    fligt 012
    from bogota at 8:00 am
    to cali at 8:20:06
    distance: 299.84 km
    speed 14.5
    299.84/14.5 = 20.6
    by maria alejandra escalante p

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  14. from bogota to cali
    it will arrive at 8:20Am
    my procedure was:300:85Km/the flight was 20 minutes

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  15. in bogota at 8
    14.5por 8= 12:00
    in cali at 12
    by daniel restepo

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  16. hello miss alethia
    b:8:00
    s:14.5
    14.5x8:116.0 in cali at:116.0
    by:esteban casas 5b

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  17. Flight # 012
    Distance from Bogota to Cali: 299.84 Km
    Km/m: 14.5
    299.84/14.5 = 20.67 ---> 20 min and 67 sec

    ReplyDelete
  18. ANSWER (Part 2):
    It will arrive at 8:20:67

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  19. 1) flight 012
    2) it arrives at 8:20am
    3) 299.84 / 14.5 = 20.67
    | |
    distance km/min
    in km from
    bogota to cali

    ReplyDelete
  20. flight # 012
    distance 299.84 km 14.5 299.84 / 14.5 = 20.67
    answer:it will arrives at 8:20 am

    ReplyDelete
  21. miss i dont understnd can you explain me tomorrow

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  22. miss plz explain me at school.

    ReplyDelete
  23. 1. 315 flight
    2. 1039.89 km X 1 min / 14.5 km=71.7 min
    71.7 min / 60= 1 hour 19 minutes.
    the plane departs at 12:30 + 1:19=1:49 pm hour that lands on pasto.
    3. so first you enter to the page to find out wath is the distance between cartagena and pasto that is 1039.89 km, now you think if the airplane flies 14.5 km/min how in much time does it will fly 1039.89 km, so I multiply 1039.89 by 1 min and divide it by 14.5 km, the answer is more than 60 min so I divide by 60 for getting it into hours.

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  24. -Flight 012
    -at 8:00a.m.
    -speed is 14.5
    -14.5 x 8=12:00m
    -arrives to Cali at 12:00m

    diego torres

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  25. fligt 012
    from bogota at 8:00am
    speed 14. 5 k/m
    14.5 x 8 = 12:00
    In cali at 12:00
    by crlos sanchez

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  26. from bogota to cali it will arrived at 8:20am

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  27. from bogota to cali you will arrived at 8:20am

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  28. 1)I CHOSE THE FLIGHT OF BOGOTA TO CALI

    2)14 x 8 = 12:00
    3)i add the time whem it departs and the speed

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  29. 1)Flight 012 bogota - cali
    2)8:00 - 8:20
    3)I divided the distance by km per min.
    299.84 / 14.5 = 20.67 min.

    Juliana Rojas 5A

    ReplyDelete
  30. 1: flight 012 bogota cali
    2:8:00 8:20
    3:i divide the distances by km permin
    299.84/14.5:20.64 minuts.felipe novoa

    ReplyDelete
  31. Hi miss the answwer (for me is):
    Flight 012
    From Bogotá to Cali, 8:00-12:00
    We arrive at 12:00
    First I multiplied 8x14:12:00
    A=At 12:00

    ReplyDelete

Thanks for your participation :)